00:03
This is the answer to chapter 11, problem number nine from the smith organic chemistry textbook.
00:10
And this problem asks us to draw an additional resonance structure for each cation.
00:16
And so one thing to notice here is that each of these cations, each of these carbocadions, is bound to an electronegative atom with a loan pair or more than one loan pair to spare.
00:32
And so all that we have to do is add the electrons from one of these loan pairs into the bond between the carbon and the heteroatom.
00:45
And that will seat this positive charge on the electron negative heteroatom.
00:54
Yeah.
00:56
And so that's the resonant structure.
00:58
So for a, that looks like this.
01:02
So our chlorine is now down to two lone pairs, and it has a positive charge on it.
01:13
So for b, it's going to be the oxygen, so a lone pair from the oxygen, add in there to give us this structure.
01:33
And now the positive charge is seated on the oxygen.
01:37
The oxygen's down to one lone pair.
01:40
And then similarly for c, the nitrogen's lone pair can add in...