Question

2 (5pt) Draw Feynman diagram Let us consider the electron and position interaction. $e^- + e^+ \rightarrow e^- + e^+$ By using Feynman diagram we can draw this process as, [Diagram showing electron-positron scattering] Figure 2: electron positron scattering This is call \"scattering process\". Here $\gamma$ is photon, and $e^+$ is positron, which is anti-particle of the electron. And one thing we should take care of is that if we assume anti-particle have positive energy, when we draw Feynman diagram it propagate backward in time. However, there is one other process is available (in tree level diagram, which means there is no loop contribution in the diagram.) which call \"anni- hilation\" process. Here electron and position collide each other and change to photon. And after some time pass, photon create electron and positron. (a) Draw Feynman diagram of \"annihilation\" process of electron and positron interaction. (Assume $x$-axis is spacial direction and $y$-axis is tem- poral direction.) This two interactions are called Bhabha scattering.

          2 (5pt) Draw Feynman diagram
Let us consider the electron and position interaction.
$e^- + e^+ \rightarrow e^- + e^+$
By using Feynman diagram we can draw this process as,
[Diagram showing electron-positron scattering]
Figure 2: electron positron scattering
This is call \"scattering process\". Here $\gamma$ is photon, and $e^+$ is positron,
which is anti-particle of the electron. And one thing we should take care
of is that if we assume anti-particle have positive energy, when we draw
Feynman diagram it propagate backward in time.
However, there is one other process is available (in tree level diagram,
which means there is no loop contribution in the diagram.) which call \"anni-
hilation\" process. Here electron and position collide each other and change
to photon. And after some time pass, photon create electron and positron.
(a) Draw Feynman diagram of \"annihilation\" process of electron and positron
interaction. (Assume $x$-axis is spacial direction and $y$-axis is tem-
poral direction.)
This two interactions are called Bhabha scattering.

2 (5pt) Draw Feynman diagram
Let us consider the electron and position interaction.
e^- + e^+ → e^- + e^+
By using Feynman diagram we can draw this process as,
[Diagram showing electron-positron scattering]
Figure 2: electron positron scattering
This is call s̈cattering process.̈ Here γ is photon, and e^+ is positron,
which is anti-particle of the electron. And one thing we should take care
of is that if we assume anti-particle have positive energy, when we draw
Feynman diagram it propagate backward in time.
However, there is one other process is available (in tree level diagram,
which means there is no loop contribution in the diagram.) which call änni-
hilationp̈rocess. Here electron and position collide each other and change
to photon. And after some time pass, photon create electron and positron.
(a) Draw Feynman diagram of ännihilationp̈rocess of electron and positron
interaction. (Assume x-axis is spacial direction and y-axis is tem-
poral direction.)
This two interactions are called Bhabha scattering.

Added by Gabriel J.

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