00:03
Hello, in this question, we need to draw the lewis structure for brf4 negative and then answer a couple of questions about it.
00:16
So let's get started with drawing the electron structure first, the lewis dot structure.
00:21
The first thing we need to know is how many valence electrons that need to go into our structure.
00:27
So bromine is a halogen in group 7a of the periodic table.
00:31
So this bromine has seven valence electrons.
00:33
We need to add that to the number of electrons from the four fluorine.
00:40
Floring is also a halogen, so each flooring has seven valence electrons also.
00:47
And then we have one unit of negative charge, which means there is one extra electron in this ion.
00:55
All right, let's add all these together.
00:58
Adding these together gives us 36, 7 plus 28 plus 1, gives us 36.
01:07
That means our finished structure, our finished lewis structure, needs to have 38 dots in it.
01:13
Let's go ahead and put that together.
01:17
Bromene being the lone atom means that it goes in the center, and it's surrounded by four fluorings.
01:30
We know that we need to use a pair of electrons between bromine and fluorine to form that single bond.
01:39
And in fact, we know fluorine can only form a single bond.
01:42
So we won't have any multiple bonds here.
01:46
Let's go ahead and start completing the octets on flooring.
01:50
Because each fluorine is going to have an octet from bonding.
02:03
Counting up our total electrons now, we have used 32...