00:01
This problem, you're looking at this molecular formula, and you're asked to draw the blue structure.
00:08
So first, let's look at how many balance electrons will have.
00:13
So we're going to add six here, and six from each oxygen, 24, and an extra two here.
00:22
So we have six plus 24, plus two.
00:27
So we get 32.
00:29
Now, here we can start by just doing single bonds everywhere, just to give us an idea of what we're looking at.
00:40
But if we look at oxygen, oxygen has six valence electrons.
00:46
So if we're to find the formal charge, we subtract the number of bonds.
00:51
So if we're looking at single bonds, we're subtracting one bond, and then each of these will have six lone periletrons.
01:00
6.
01:01
We get negative 1.
01:04
And if we look at telerium, what we're going to do is very similar...