Draw one Lewis structure that obeys the octet rule of XO3^-2. Draw one Lewis structure that best minimizes the formal charge of XO3^-2 (label all non-zero formal charges by each atom).
Added by Amparo S.
Step 1
Oxygen has 6 valence electrons, and there is one oxygen atom in XO3^-2, so we have 6 valence electrons. Additionally, the charge of -2 means we need to add 2 more electrons. Total valence electrons = 6 (from oxygen) + 2 (from the charge) = 8 electrons ** Show more…
Show all steps
Your feedback will help us improve your experience
Hitendra Singh and 94 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Draw two Lewis structures for a molecule with the chemical formula C5H7NO. All atoms in your structures must obey the octet rule and have optimal formal charges.
Madhur L.
Write a Lewis structure that obeys the octet rule for BrO3- and assign formal charges to each atom. Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons and formal charges.
Brooke S.
Draw a Lewis structure with lowest formal charges for $\mathrm{MnO}_{4}^{-}$.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
600,000+
Students learning Chemistry with Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD