00:01
In this problem, we're given this tertiary alcohol, and we're told this is the product of an oxymarcuration reaction.
00:10
So in this type of reaction, we have a double between carbons, and then we end up with a single bond between them, and an alcohol added on one and a hydrogen on the other.
00:22
Now, this is what we call a markovnikov edition, and that means that our alcohol goes on, the most substituted carbon over the double bond.
00:38
So if we look at where our alcohol is, we know that carbon had to be in a double bond.
00:45
So it was either in a double bond with this carbon, this carbon, or this carbon.
00:52
So if it was for this carbon, this carbon is secondary, and this is tertiary.
01:01
So the alcohol would end up on the carbon that we have.
01:04
So that's going to be one answer that we have...