00:01
So, we have given some iupac names here and systematic names and we have to draw the correct structures for them.
00:08
So, first of all we have 4e 2 ,4 -dimethylhexane 1 ,4 -diene.
00:29
Hexa hex prefix indicates that we have six carbon atoms one two three four five and six okay now on first and on fourth position we have double bond then on second position we have methyl group group and on fourth position also we have methyl group okay completing the valencies for rest of them so here we require one hydrogen atom here three hydrogen atom here two hydrogen atom here valency is completed and here we require two hydrogen atom okay so this is my structure so, now you can see first, second, third, fourth, fifth, sixth you can see on second position and fourth position we have methyl group repeated for two times that's why di prefix is used.
01:42
Similarly, double bound is being repeated for two times so that's why di prefix is used for diene and now we have e configuration this means that the methyl substituents are are opposite to each other.
01:57
Okay.
01:57
The substituent atoms to the double bonded carbon atom, they are opposite to each other.
02:02
That's why e configuration.
02:04
Moving on to next b part.
02:07
We have cis 3, 3 dimethyl 4 propyl octa 1, 5 diene.
02:34
Okay.
02:35
Ok, so now octa means that we have 8 carbon atoms and on 1st and 5th position we have 2 double bonds.
02:43
Ok, so now we can write that 1, 2, 3, 4, 5, 6, 7, 8.
02:59
Now it says 3, 3 dimethyl.
03:02
This means on 3rd position we have 2 methyl groups.
03:05
4.
03:07
Profile groups c3h8 octa15 die in on 1st position we have double bond and on 5th position we have double bond 6.
03:31
Sys configuration okay now this configuration is when the same substituent are attached on same side of the double bonded carbon atom this is configuration cannot be shown for the terminal carbon atom so that's why this will remain as usual okay so complete the valency carbon is tetravalent in nature keeping that in mind we require two and one hydrogen atom respectively for this the valency is already completed and for this carbon we require one hydrogen atom okay now so now let me draw it again so we have a structure here now here we require one hydrogen atom and here also we require one hydrogen atom to complete the valency carbon is tetravalent in nature so now you can see that the hydrogen atom are present the same hydrogen atom are present on same side right now here we require two hydrogen atom to complete valency here we require three hydrogen atom to complete valency okay so now let me number them one two three four five six seven eight okay so on third position we have two methyl group on fourth position we have propyl group and on first and fifth position we have two double bonds so double bond are being repeated for two times that's why di prefix and that is the required structure we have a cis configuration here for this double bonded carbon atom okay now moving on to next c part 4 methyl penta 1 2 2 diene ok so now pant prefix this means that we have 5 carbon atom 1 2 3 4 5 4 methyl this means on 4 position we have methyl group 1 2 diene means that on double bond is present went on first position and second position also okay four methyl this means yeah this i have done so now completing the valencies here we require two hydrogen atom here valency is already completed here we require one hydrogen atom okay and here we require one hydrogen atom here we require three hydrogen atom that is the complete structure okay now moving on to so let me number them to make you short one two three four five you can clearly see now right on first and second position we have double bond for two times so die prefix is used and on fourth position we have methyl group.
06:50
Moving on to next structure d part.
06:56
So, we have 3e5z2, 6 dimethyl octa 1, 3, 5, 7 tetraene.
07:23
Okay...