Question

Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol: a. acetic acid b. pentanoic acid

          Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol:
a. acetic acid
b. pentanoic acid

Added by Michelle R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Shalini Tyagi

08/18/2022

Step 1

Acetic acid reacting with methyl alcohol will form methyl acetate. The condensed structural formula for methyl acetate is CH3COOCH3. Show more…

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Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol: a. acetic acid b. pentanoic acid

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Transcript

00:01 So first of all we have acetic acid now the structure can be drawn like ch3 c double bond o o so this is here called as acetic acid so now it is reacted with methanol that is c h so now when the carboglycic acids are reacted with alcohol in the presence of acids like h2 s4 so this leads to formation of ester now how will you form ester actually the acid like we have h positive wine here okay we have a strong acid like h2 s4 so it donates h positive ion so it released to elimination of h2 okay water molecule okay so you all have to do is remove the water molecule okay so i can draw the structure of methanol like this okay so now what i said is here if i remove hydrogen from here and oh h part from here so this will lead to form ch3 c double bond o o c h 3 so this is the ester we have and here we removed the h2o okay so now what is the name for this ester so this is called as methyl ethanoate so here along with this acid we have also heat the composition we have okay we heat the acidic acid along with methanolol and this to formation of ester and this whole process is called esterification now the next one is this time we have pentanoic acid so when i have pentanoic acid so this means that i have five carbon atoms so ph three c h two c h two and then c double bond o o -h okay so this is pentanoic acid structure it is reacted with methanol so this is here methanol so again it will be reacted in the presence of acid it is heated and this leads to elimination of water molecule so we will remove oh part from here and hydrogen part from here so this will lead to form ch3 ch2 ch2 ch2 ch2 c double bond o o c h3 so here see in the alcoholic part okay in the alcohol we have this methyl substituent test okay so this will be treated as as an alkyl part here so this will be called as methyl okay and now of course since it is ester so the suffix will be 08 okay so now here we have from the carboxylic acid chain we have five carbon atoms so that is here pantanoate okay so this will be called as pentanoid so so methyl pentanoate, it is the name of this acid...

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