0:00
Okay.
00:02
I'm assuming that your molecule looks something like this, what's shown there.
00:11
And we need to determine what's the most stable radical that can result from the breaking of a ch bond.
00:16
So i'm just going to draw in one h, one hydrogen on every carbon here.
00:23
There's a hydrogen there.
00:24
There's a hydrogen there.
00:26
There's one here.
00:28
There's one here.
00:29
Now, of course, there are multiple hydrogens on all of these carbons, for example.
00:34
There's three here, two here, two here, three here, three here.
00:40
Only one there, but you get the point.
00:43
So the question is, if i were to take, let's say, this ch bond and break it and replace it with the radical, what would i get? i would get the phone.
00:56
I would get this radical on that carbon.
00:59
That's what the question is asking is saying, go through this molecule and consider what the point...