0:00
Hey, hello everyone.
00:01
In this question we have to find out the particular electronic configuration or the orbital diagram of the neobium and after the way we have to find out whether it is a diamagnetic or paramagnetic.
00:14
First of all we have that particular atom which is called neobium and the symbol of this atom is simply n b and that electronic configuration is simply what krypton which is a noble gas and and the electronic, sorry, the atomic number is 36 and which is a stable atom, after the krypton it is coming out as a 4d 4, 5 as 1.
00:43
So this is the particular electronic configuration of neobium and from this we can draw the orbital diagram of it.
00:51
So simply we can draw here it is 4d, that is 5 orbitals will be there in the case of d orbital 1, 2, 3, 4, 5.
01:00
And for p orbital that is 3 1 2 3 and for s that is 1 so here it is 4d here it is 5p and here it is 5 s after the i will fill the electrons as per the electronic configuration and that is what here in the case of 4d we have 4 electrons so 1 2 3 4 and for 5 p this is vacant and for 5 s this is only 1 so so here it is the orbital diagram of the neobium and here we can clearly see five unpaid electrons are present.
01:38
How many unpaid electrons are present? five unpaired electrons are present...