Draw the organic product of the reaction below. Show stereochemistry when relevant. If the product exists as a pair of enantiomers, draw only one. 1. $LiAlH_4$ 2. $H_2O$ Click and drag to start drawing a structure.
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$LiAlH_4$ is a strong reducing agent that can open epoxides. The reaction proceeds via $S_N2$ mechanism, where the hydride attacks the less substituted carbon of the epoxide. Show more…
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