3. Draw the reaction mechanism using electron-pushing arrows...

3. Draw the reaction mechanism using electron-pushing arrows for the transformation below in the box provided. All reagents needed are provided in the reaction scheme. OH $H_3O^+$ heat

Transcript

00:01 Hello everyone, let's look at the question.

00:03 Now in this question we have given a reaction and we have to draw a mechanism using a curved arrows and then we have to predict which side of the reaction is favored under equilibrium condition right so here the given reaction is so here it is double bond s s h let me write like this only so here the lone pair of electrons are all mentioned so here two lone pair of electrons and here also two lone pair of electrons are there right now this is reacting with sh minus which is having three lone pair of electrons right so this is giving see here if we use the curved arrows see sh minus so this is having extra electrons right and this proton is as a decay in nature because it is in this loan pair of electron is involved in what resonance so that so this bond becomes weaker and this will abstain the proton and then this lone pair of electron will go here okay now so now it becomes so ch3 double bond s and here one two three or totally six electrons so that's why it's just carrying negative charge and here it is h2 s so one two three four okay now so this is the balance the equation sorry this is the the mechanism for this reaction and using this curved arrows see here now we have to explain which side of the reaction is favored see we have an in this case so this is acting as what base and this is acting as an acid and in the reverse reaction so this will accept the proton so this will act as an acid and this will act as a base okay now here if we compare the stability of the anion so this anion is more stable right because it is involved in the resonance so if i show here see shh 3 c double bond o sorry c double bond s and here also s minus so this will be involved in the resonance so this is resonance stabilized okay sorry so this is resonance stabilized okay so this anion is more stable that means so this is what the more sdk nature right therefore if we see the which side of the reaction is favored so it is the forward reaction is favored right so here, forward reaction is favored in the equilibrium...

Question

3. Draw the reaction mechanism using electron-pushing arrows for the transformation below in the box provided. All reagents needed are provided in the reaction scheme. OH $H_3O^+$ heat

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