00:01
Here we need to draw the structure for 3 .4 dimethyl cyclodecine.
00:19
So this is diomethyl cyclodecine.
00:21
That is, this is closed chain of 10 carbon atoms.
00:27
So let us just draw 10 carbon atoms as closed chain.
00:32
So c, c, c, c, c, c, c, c, c, c, c, c, c, seven, seven, eight, eight, okay, this is nine, and this is ten.
01:10
Now, this is three, four, dimethyl cyclo, so let us just try to naming it.
01:16
One two three four five six seven eight nine ten we are naming the carbon atoms so dimethyl cyclode dekine so dimethyl three four three and four dimethyl so let us write c s three here and ch three here this is this becomes three four dimethyl cyclo dekine dekine this is alkyne alkyne alkyne so must have triple bond okay so three four dimethyl cyclo dekine so let us just draw triple bond so anywhere we can draw triple bond like this okay now if we compensate with hydrogen it will become two c s2 c s2 simply c h okay it has three ch.
02:24
It has 3 plus 1, 4 bonds...