00:01
Hello students, let's solve this question.
00:03
Here it is given that the impedance i .e.
00:05
X1 is equal to 0 .24 ohm and the turns ratio is equal to n2 divided by n1 and it is 10.
00:18
And the power delivered by the transformer bank is 100 mw and it can be written as 230 kv.
00:30
Now for the first part of the question, let's find out the voltage magnitude for that we can use s is equal to p0 divided by cos phi.
00:41
Let's substitute the values s will be equal to 100 into 10 raised to 6 divided by 0 .8.
00:49
Hence s will be equal to 125 mw.
00:55
Now the current magnitude through the road is i2 is equal to 125 into 10 raised to 6 divided by 230 into 10 raised to 3.
01:08
We will get current i2 is equal to 543 .44 minus 36 .86.
01:21
So phi will be equal to cos inverse of 0 .8 and it is minus 36 .86.
01:30
Now the current transferred from the primary side is i1 divided by i2 which is equal to k.
01:39
Therefore i1 will be equal to k into i2.
01:44
Substituting the values gives 10 into 543 .47 where k is the ions ratio.
01:54
Therefore i1 will be equal to 5434 .7 a.
02:02
Now for delta connected transformer, il is equal to i1 divided by root 3...