To solve exponential equations or logarithmic equations, we have some commonly used methods:
i) Apply the equivalent relation y = ax or x = loga y
ii) Apply properties so that we can have the form of exponent equals exponent (logarithm = logarithm) with the same base, so that we can simplify the equation to linear or quadratic
iii) Use substitution to change the original equation into a quadratic equation
Now, use the two methods above to solve the following equations:
1) 25x - 1 = 3
2) logx + log6x - 1 = 1
3) e^(2x) - 3e^x = 10