00:01
Hello everyone we are going to understand this question here given in the question a 20 kg box is placed on incline plane so mass of the box mass of box that is represented by m which is 20 kg which is placed on the inclined plane angle of inclination of incline plane angle of inclination that is theta which is 20 degree now let's draw the free body diagram this is angle of inclination.
00:45
Box is placed on the incline plane.
00:47
Weight of the box that is mg.
00:49
Now taking the component of weight that is mg cos theta and along to incline plane that is mg sine theta.
01:00
This is the normal reaction and friction force is in upward direction.
01:04
Here block is in stationary state.
01:10
Block is in stationary state.
01:20
So in the part a we have to draw the free body diagram.
01:25
So weight of the block that is downward.
01:27
This is the required free body diagram which is again we can write.
01:31
This is the friction force.
01:34
This is the component of weight along to incline plane that is mg sign 20 or mg sine theta...