During a chemistry class, David was asked to add pure acid to 6 liters of 45% acid solution, to get a solution which is 80% acid. How much water should he add?
Added by Angela R.
Step 1
Pure acid in 45% solution = 6 liters * 0.45 = 2.7 liters Now, let's assume that David adds x liters of pure acid to the solution. The total volume of the solution will be 6 + x liters, and the total amount of pure acid will be 2.7 + x liters. We want the final Show more…
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