During a fireworks display, a shell is shot into the air with an initial speed of 63.0 m/s at an angle of 42.0° above the horizontal. The fuse is timed to ignite the shell just as it reaches its highest point above the ground. Calculate the height at which the shell explodes?
Added by Kim B.
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We can do this using the formula v = v0 * sin(θ), where v0 is the initial speed and θ is the angle. So, v = 63.0 m/s * sin(42.00) = 42.3 m/s. Show more…
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