Since the shot starts from rest, $u = 0$. Plugging in the given values, we get:
$(16\,\text{m/s})^2 = 0 + 2a(1.6\,\text{m})$
Solving for $a$, we get:
$a = \frac{(16\,\text{m/s})^2}{2(1.6\,\text{m})} = 80\,\text{m/s}^2$
So the acceleration of the shot is
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