Question

During an ice show, a 60.0 -kg skater leaps into the air and is caught by an initially stationary 75.0 -kg skater. (a) What is their final velocity assuming negligible friction and that the 60.0-kg skater's original horizontal velocity is 4.00 m/s? (b) How much kinetic energy is lost?

          During an ice show, a 60.0 -kg skater leaps into the air and is caught by an initially stationary 75.0 -kg skater. (a) What is their final velocity assuming negligible friction and that the 60.0-kg skater's original horizontal velocity is 4.00 m/s? (b) How much kinetic energy is lost?

Added by Douglas B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Krishna G

01/24/2022

Step 1

Given: - Mass of skater 1 (m1) = 60.0 kg - Initial velocity of skater 1 (v1) = 4.00 m/s - Mass of skater 2 (m2) = 75.0 kg - Initial velocity of skater 2 (v2) = 0 m/s Using the law of conservation of linear momentum: m1v1 + m2v2 = (m1 + m2)vf (60.0 kg)(4.00 m/s) + Show more…

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During an ice show, a 60.0 -kg skater leaps into the air and is caught by an initially stationary 75.0 -kg skater. (a) What is their final velocity assuming negligible friction and that the 60.0-kg skater's original horizontal velocity is 4.00 m/s? (b) How much kinetic energy is lost?