During the Cold War, the Premier of the Soviet Union threatened the United States with 7.0 megaton\newline$^{239}Pu$ warheads. (Each would have yielded the equivalent of an explosion of 7.0 megatons of TNT,\newlinewhere 1 megaton of TNT releases $2.6 \times 10^{28}$ MeV.) If the plutonium that actually fissioned had been\newline9.53% of the total mass of the plutonium in such a warhead, what was that total mass?
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To find the total mass of plutonium in the warhead, we need to multiply the percentage of plutonium by the total mass of the warhead. Total mass of plutonium = 9.53% * Total mass of the warhead Show more…
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During the Cold War, the Premier of the Soviet Union threatened the United States with $2.0$ megaton ${ }^{239} \mathrm{Pu}$ warheads. (Each would have yielded the equivalent of an explosion of $2.0$ megatons of TNT, where 1 megaton of TNT releases $2.6 \times 10^{28} \mathrm{MeV}$ of energy.) If the plutonium that actually fissioned had been $8.00 \%$ of the total mass of the plutonium in such a warhead, what was that total mass?
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