e 10 pts 15 pts 2 1 if sin 513 and tan 0 find sec given that sin 513 and tan 0 we can determine

Name: e 10 pts 15 pts 2 1 if sin 513 and tan 0 find sec given that sin 513 and tan 0 we can determine that cos 0 using the pythagorean identity we have cos2 sin2 1 cos2 5132 1 cos2 25169 1 cos2 1 07753
Uploaded: 2022-04-20T17:03:01-08:00
Duration: 1 min 40 s
Channel: Alison Rodriguez
Description: e 10 pts 15 pts 2 1 if sin 513 and tan 0 find sec given that sin 513 and tan 0 we can determine that cos 0 using the pythagorean identity we have cos2 sin2 1 cos2 5132 1 cos2 25169 1 cos2 1 07753

To begin with here, we're told that sign of A is negative 3 over 5 in quadrant 3. So what I'm go

Question

E (10 pts) (15 pts) 2. 1. If sinθ = 5/13 and tanθ < 0, find secθ. Given that sinθ = 5/13 and tanθ < 0, we can determine that cosθ < 0. Using the Pythagorean identity, we have: cos^2θ + sin^2θ = 1 cos^2θ + (5/13)^2 = 1 cos^2θ + 25/169 = 1 cos^2θ = 1 - 25/169 cos^2θ = 144/169 cosθ = -12/13 secθ = 1/cosθ secθ = -13/12

          E (10 pts) (15 pts) 2. 1. If sinθ = 5/13 and tanθ < 0, find secθ. 
Given that sinθ = 5/13 and tanθ < 0, we can determine that cosθ < 0. 
Using the Pythagorean identity, we have: 
cos^2θ + sin^2θ = 1 
cos^2θ + (5/13)^2 = 1 
cos^2θ + 25/169 = 1 
cos^2θ = 1 - 25/169 
cos^2θ = 144/169 
cosθ = -12/13 
secθ = 1/cosθ 
secθ = -13/12

Added by Jack W.

Precalculus with Limits

Ron Larson 2nd Edition

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E (10 pts) (15 pts) 2. 1. If sinθ = 5/13 and tanθ < 0, find secθ. Given that sinθ = 5/13 and tanθ < 0, we can determine that cosθ < 0. Using the Pythagorean identity, we have: cos^2θ + sin^2θ = 1 cos^2θ + (5/13)^2 = 1 cos^2θ + 25/169 = 1 cos^2θ = 1 - 25/169 cos^2θ = 144/169 cosθ = -12/13 secθ = 1/cosθ secθ = -13/12