P8-138 In this problem, the complex reactions described below will first be carried out in the liquid phase (Parts (a) through (d)) and then in the gas phase. (Parts (e) through (g)). One need not solve the liquid phase to solve the gas phase problems. The following reactions are carried out isothermally. A+2B$\rightarrow$C+D $r_{1D} = k_{1D}C_AC_B$ 2D+3A$\rightarrow$C+E $r_{2E} = k_{2E}C_A^2C_D$ B+2C$\rightarrow$D+F $r_{3F} = k_{3F}C_BC_C^2$ Additional information: $k_{1D} = 0.25\text{ dm}^3/ ext{mol}^2\cdot ext{min}$ $v_0 = 10\text{ dm}^3/ ext{min}$ $k_{2E} = 0.1\text{ dm}^3/ ext{mol}\cdot ext{min}$ $C_{A0} = 1.5\text{ mol/dm}^3$ $k_{3E} = 5.0\text{ dm}^3/ ext{mol}^2\cdot ext{min}$ $C_{B0} = 2.0\text{ mol/dm}^3$ (a) Consider the reactions to be liquid phase and plot the species concentra- tions and the conversion of A as a function of the distance (i.e., volume) down a 50-dm³ PFR. Note any maxima. (b) Consider the reactions to be liquid phase and determine the effluent concen- trations and conversion from a 50-dm³ CSTR. (Ans.: $C_A = 0.61$, $C_B = 0.79$, $C_F = 0.25$, and $C_D = 0.45\text{ mol/dm}^3$.) (c) Plot
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- Reaction 1: A + 2B → C + D, rate \( r_{1D} = k_{1D} C_A C_B \) - Reaction 2: 2D + 3A → C + E, rate \( r_{2E} = k_{2E} C_A^2 C_D \) - Reaction 3: B + 2C → D + F, rate \( r_{3F} = k_{3F} C_B C_C^2 \) Show more…
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