Question

Each of the electrons in a particle beam has a kinetic energy of $1.60 \times 10^{-17} \mathrm{J}$ . (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' move- ment) that will stop these electrons in a distance of 10.0 $\mathrm{cm}$ ? (b) How long will it take to stop the electrons? (c) After the electrons stop, what will they do? Explain.

          Each of the electrons in a particle beam has a kinetic energy of $1.60 \times 10^{-17} \mathrm{J}$ . (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' move-
ment) that will stop these electrons in a distance of 10.0 $\mathrm{cm}$ ? (b) How long will it take to stop the electrons? (c) After the electrons stop, what will they do? Explain.

Added by Amanda N.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

12/22/2021

Step 1

0 cm. Given: Kinetic energy of each electron, $KE = 1.60 \times 10^{-17} J$ Distance, $d = 10.0 cm = 0.1 m$ The work done by the electric field to stop the electrons is equal to the kinetic energy of the electrons: \[W = Q \cdot E \cdot d = KE\] \[E = Show more…

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Each of the electrons in a particle beam has a kinetic energy of $1.60 \times 10^{-17} \mathrm{J}$ . (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' move- ment) that will stop these electrons in a distance of 10.0 $\mathrm{cm}$ ? (b) How long will it take to stop the electrons? (c) After the electrons stop, what will they do? Explain.