00:01
Here in this question, each of the following alcohols has been subjected to acid catalyzed dehydration and yields a mixture of two isomeric alkanes.
00:13
Identify the two alkenes in each case and predict which one is the major product on the basis of sad sephru.
00:24
Okay, so in case of a, that is the first one, there is, two possibility of dehydration and formation of alken.
00:36
One is ch3 c, one more ch3 here and then double bond is coming here if this adjacent hydrogen is removed as water with oh.
01:03
So here one ch 3 and one ch3 is here.
01:12
So this is one possibility and second possibility is when this side that means alpha carbon is this one also alpha hydrogen can be removed from here.
01:28
So by that the product will be ch2 double bond c, ch3, and one more c, h, ch3, and one more c, c, h, ch3.
01:48
Is attest here.
01:52
So these are two possibilities say in case of a molecule which is given.
02:00
So out of these two the major product will be this one.
02:08
First one...