Question

ECE 301 3. Using the current division principle, determine V, i.e., the voltage across the 3-? resistor in the circuit of Figure 3. (20 points) (Note: This problem is required to be solved with the current division principle.) 5 A $I_x = 5A(\frac{\frac{1}{2}}{\frac{1}{2} + \frac{1}{3}}) = 5A(\frac{3}{5}) = 3A$ $V = 3I_x = 3(3) = 9V$ 2 ? 3 ? V Figure 3.

          ECE 301
3. Using the current division principle, determine V, i.e., the voltage across the 3-? resistor
in the circuit of Figure 3. (20 points)
(Note: This problem is required to be solved with the current division principle.)
5 A
$I_x = 5A(\frac{\frac{1}{2}}{\frac{1}{2} + \frac{1}{3}}) = 5A(\frac{3}{5}) = 3A$
$V = 3I_x = 3(3) = 9V$
2 ?
3 ?
V
Figure 3.

ECE 301
3. Using the current division principle, determine V, i.e., the voltage across the 3-? resistor
in the circuit of Figure 3. (20 points)
(Note: This problem is required to be solved with the current division principle.)
5 A
Ix = 5A(((1)/(2))/((1)/(2) + (1)/(3))) = 5A((3)/(5)) = 3A
V = 3Ix = 3(3) = 9V
2 ?
3 ?
V
Figure 3.

Added by Matthew D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

Step 1

First, let's label the currents in the circuit. Let's call the current through the 6-ohm resistor I1, the current through the 3-ohm resistor I2, and the current through the 2-ohm resistor I3. Show more…

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ECE301 3. Using the current division principle, determine V, i.e., the voltage across the 3-ohm resistor in the circuit of Figure 3. (20 points) (Note: This problem is required to be solved with the current division principle.) Figure 3