A parallel-plate capacitor with plate area A = 1.20 m² and plate separation d = 4.03 x 10?? m is fully charged. The potential difference across the plates is V = 105 volts. What is the energy density, u in J/m³, of the capacitor? Assume that the dielectric constant is 1.0. Take ?? = 8.85 x 10?¹² C²/Nm². Please round your answer to two decimal places. Energy density is defined as energy per volume. Equations: Energy, U = ½CV² where C = ??(A/d). Volume = Ad

Name: A parallel-plate capacitor with plate area A = 1.20 m² and plate separation d = 4.03 x 10?? m is fully charged. The potential difference across the plates is V = 105 volts. What is the energy density, u in J/m³, of the capacitor? Assume that the dielectric constant is 1.0. Take ?? = 8.85 x 10?¹² C²/Nm². Please round your answer to two decimal places. Energy density is defined as energy per volume. Equations: Energy, U = ½CV² where C = ??(A/d). Volume = Ad
Uploaded: 2023-01-25T15:41:24-08:00
Duration: 1 min 19 s
Channel: Sri K

          A parallel-plate capacitor with plate area A = 1.20 m² and plate separation d = 4.03 x 10?? m is fully charged. The potential difference across the plates is V = 105 volts. What is the energy density, u in J/m³, of the capacitor? Assume that the dielectric constant is 1.0. Take ?? = 8.85 x 10?¹² C²/Nm². Please round your answer to two decimal places. Energy density is defined as energy per volume. Equations: Energy, U = ½CV² where C = ??(A/d). Volume = Ad

A parallel-plate capacitor with plate area A = 1.20 m² and plate separation d = 4.03 x 10?? m is fully charged. The potential difference across the plates is V = 105 volts. What is the energy density, u in J/m³, of the capacitor? Assume that the dielectric constant is 1.0. Take ?? = 8.85 x 10?¹² C²/Nm². Please round your answer to two decimal places. Energy density is defined as energy per volume. Equations: Energy, U = ½CV² where C = ??(A/d). Volume = Ad

Added by Marta G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

01/25/2023

Step 1

85 x 10^(-12) F/m (permittivity of free space), A = 1.20 m² (plate area), and d = 4.03 x 10^(-4) m (plate separation). C = (8.85 x 10^(-12) F/m) * (1.20 m²) / (4.03 x 10^(-4) m) Now, we need to find the energy (U) stored in the capacitor using the formula: U = Show more…

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A parallel-plate capacitor with plate area A = 1.20 m² and plate separation d = 4.03 x 10⁻⁴ m is fully charged. The potential difference across the plates is V = 105 volts. What is the energy density, u in J/m³, of the capacitor? Assume that the dielectric constant is 1.0. Take ε₀ = 8.85 x 10⁻¹² C²/Nm². Please round your answer to two decimal places. Energy density is defined as energy per volume. Equations: Energy, U = ½CV² where C = ε₀(A/d).