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EE 2353-002 Fall 2017 Practice Problems, Part 2 - R. von Borries 10 24 Average Power - Mean Square Value The complex exponential Fourier series of a periodic signal $f(t)$ is given by $\infty$ $f(t) = \sum_{n=-\infty} D_n e^{jn\omega_0 t}$, (1) for $-\infty < t < \infty$. Write the average power of $f(t)$ in terms of the coefficients of the complex exponential Fourier series in (1). Use the following expression to find the average power or the mean-square value (MS): $MS = \frac{1}{T_0} \int_{T_0} |f(t)|^2 dt = \frac{1}{T_0} \int_{T_0} f(t) f^(t) dt$, where $f^(t)$ denotes the complex conjugate of $f(t)$.

          EE 2353-002 Fall 2017 Practice Problems, Part 2 - R. von Borries 10
24 Average Power - Mean Square Value
The complex exponential Fourier series of a periodic signal $f(t)$ is given by
$\infty$
$f(t) = \sum_{n=-\infty} D_n e^{jn\omega_0 t}$,
(1)
for $-\infty < t < \infty$. Write the average power of $f(t)$ in terms of the coefficients of the complex
exponential Fourier series in (1). Use the following expression to find the average power or
the mean-square value (MS):
$MS = \frac{1}{T_0} \int_{T_0} |f(t)|^2 dt = \frac{1}{T_0} \int_{T_0} f(t) f^*(t) dt$,
where $f^*(t)$ denotes the complex conjugate of $f(t)$.

EE 2353-002 Fall 2017 Practice Problems, Part 2 - R. von Borries 10
24 Average Power - Mean Square Value
The complex exponential Fourier series of a periodic signal f(t) is given by
∞
f(t) = ∑n=-∞ Dn e^jnω0 t,
(1)
for -∞ < t < ∞. Write the average power of f(t) in terms of the coefficients of the complex
exponential Fourier series in (1). Use the following expression to find the average power or
the mean-square value (MS):
MS = (1)/(T0)∫T0 |f(t)|^2 dt = (1)/(T0)∫T0 f(t) f^*(t) dt,
where f^*(t) denotes the complex conjugate of f(t).

Added by Andres C.

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