Electric field of a single point charge: The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C. What is the charge on the object? (k = 1/4ĻĪµā = 8.99 Ć 10ā¹ N ā mĀ²/CĀ²)
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99 Ć 10ā¹ N ā mĀ²/CĀ²), q is the charge, and r is the distance from the charge. We are given that E = 180,000 N/C and r = 1.5 cm = 0.015 m. We are asked to find q. Rearranging the formula to solve for q gives: Show moreā¦
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