00:01
So everyone, we are going to understand this question here given in the question given distance between two proton, distance between two proton that it is represented by d, which is given 0 .75 nanometer.
00:38
Or we can write 0 .75 into 10 to the power minus 9 meter.
00:46
And charge on proton charge on proton qp is equal to 1 .6 into 10 to the power minus 19 kudom and mass of proton mass of proton mp is equal to 1 .67 into 10 to 10 to the power minus 27 kg and we have to find the maximum velocity of the proton when maximum velocity is the proton will be maximum and we have to find the value of maximum velocity of proton.
01:39
Now when the distance between both proton is minimum then at that and when we will release then we will see that the maximum velocity at the same time it will have the maximum velocity or we can write half mv square is equal equal to k q square upon d means when potential energy between proton will be minimum at the same time kinetic energy will be maximum so we can write v square is equal to 2 k k p square upon d or we can write v is equal to square root of 2 k q square p upon d now substituting the value in this so we can write 2 into 9 into 10 to the power 9 and value of q is 1 .6 into 10 to the power minus 19 square upon value of d that is 0 .75 into 10 to the power.
02:58
Here we forgot to write mass of proton because when we will do the cross product then mass of proton will be in denominator like this into 2 0 .75 value of d is 0 .75 into 10 to minus 9 and value of mass of proton that is given 1 .27 sorry 1 .67 into 10 to the power minus 27 1 .67 into 10 to the power minus 27 kg.
03:33
Now after further calculation we will get b is equal to square root of 30, sorry, 46 .08 into 10 to the power 9 into 10 to the power minus 38 upon 1 .25 into 10 to the power minus 37.
04:11
10 to the over minus 36.
04:14
Now after doing the further calculation we will get v is equal to square root of 36 .6, 36 .86 into 10 to the power 7 or we can write square root of 3 .686 into 10 to the power 8.
04:35
Now after doing the calculation we will get v is equal to 1 .91 into 10 to the power 4 meter per second...