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The Convolution Integral • Convolution operation given symbol '' y(t) = x(t) h(t) = \int_{-\infty}^{\infty} x(\tau)h(t - \tau)d\tau \"y\" equals \"x\" convolved with \"h\"

          The Convolution Integral

• Convolution operation given symbol '*'

y(t) = x(t) * h(t) = \int_{-\infty}^{\infty} x(\tau)h(t - \tau)d\tau

\"y\" equals \"x\" convolved with \"h\"

$The Convolution Integral • Convolution operation given symbol '*' y(t) = x(t) * h(t) = \int{-\infty}^{\infty} x(\tau)h(t - \tau)d\tau \"y\" equals \"x\" convolved with \"h\"$

Added by Natalie P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Animesh Raj

Step 1

We are given two functions to convolve: - $x(t) = e^{-3t}[u(t) - u(t - 3)]$ - $h(t) = e^{-2t}[u(t) - u(t - 1)]$ The convolution integral is defined as: \[y(t) = \int_{-\infty}^{\infty} x(\tau)h(t - \tau)d\tau\] Show more…

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Electrical Engineering: Signals & Systems Determine the convolution of x(t) = e^(-3t)[u(t) - u(t - 3)] and h(t) = e^(-2t)[u(t) - u(t - 1)] using the convolution integral. The Convolution Integral: The convolution operation is given the symbol **. y(t) = x(t) ** h(t - T) dt "y" equals "x" convolved with "h