Consider the circuit given below, where RE = 5.1kΩ, B = 125, and Vee = 0.7V. Calculate the collector-emitter voltage. Round the final answer to one decimal place.
Vcc = +20V
Rc = 10kΩ
VBB = +2.5V
RE = WI
Since 2N3906 has a large β value, le lc. Calculate Vce.
Vcc = +10V
R2 = 2.2kΩ
RE = 1kΩ
2N3906
SR = 10
Rc = 3.6Ω