Elimination Reactions and Alkenes Problem-Solving Activity Indicate which mechanism each reaction will follow. Draw the major product(s) for each reaction. KOH NaOH NaOH EtOH KOH acetone
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KOH: This is a strong base and can lead to elimination reactions. The mechanism will be E2 (bimolecular elimination). The major product will be an alkene. For example, if we start with 2-bromo-2-methylpropane, the major product will be 2-methylpropene. Show more…
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1. Predict the elimination products of the following reactions. When two alkenes are possible, predict which one will be the major product. Explain your answers, showing the degree of substitution of each double bond in the products. 2. Which of these reactions are likely to produce both elimination and substitution products? (a) 2 -bromopentane $+\mathrm{NaOCH}_{3}$ (b) 3 -bromo-3-methylpentane $+\mathrm{NaOMe}\left(\mathrm{Me}=\right.$ methyl, $\mathrm{CH}_{3}$ ) (c) 2-bromo-3-ethylpentane $+\mathrm{NaOH}$ (d) cis-1-bromo-2-methylcyclohexane $+\mathrm{NaOEt} \quad\left(\mathrm{Et}=\right.$ ethyl $\left.\mathrm{CH}_{2} \mathrm{CH}_{3}\right)$
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