00:01
For this problem, we are given a sample that contains copper and oxygen.
00:04
It has a mass of 0 .6349 grams, and of that, 0 .5639 grams of that are copper.
00:11
So the first thing we need to do is find our moles of copper.
00:15
So 0 .5639 divided by 63 .546 is 0 .008874 moles of cu.
00:37
Next, we need to find our grams of oxygen.
00:40
So we would take 0 .6349, which is our whole sample, minus 0 .5639, which is the copper, 0 .6349 minus 0 .5639, which gives you 0 .071 grams of oxygen.
01:05
And then we need to change that so the sample has just cu and o.
01:10
So if you know this many grams are cu, the rest has to be the oxygen.
01:13
Then we are going to change our grams of o into moles.
01:19
So we'll divide that by its molar mass, which is 15 .999.
01:25
So divided by 15 .999, and that gives you 0 .004438 moles of o...