00:01
Here in this problem, given energy in the amount of 460 joules is added to a 25 gram sample of water at a temperature of 15 degrees celsius.
00:12
What will be the final temperature and specific heat of water given 4186 joules per kilogram per degree celsius.
00:23
Now recall the formula q is equal to m, c, delta t.
00:29
Delta t is the difference in temperature, c specific heat capacity of the water, a mass of the substance, here mass of water, and q is the heat given here.
00:42
So we can calculate delta t.
00:44
That will be q divided by m, c.
00:48
Here, c given 4186 joules per kilogram per degree celsius.
00:57
Now we know one kilogram is thousand grams...