Enter your answer in the provided box. Calculate the following quantity: volume of 1.87 M calcium chloride that must be diluted with water to prepare 871 mL of a 1.45 × 10⁻² M chloride ion solution. mL
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Step 1
The molarity of chloride ions is given as 1.45 × 10^-2 M, and the volume is 871 mL or 0.871 L. Moles of chloride ions = Molarity × Volume = 1.45 × 10^-2 M × 0.871 L = 1.26 × 10^-2 moles Show more…
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