00:01
So in this question you have to find out the enthalpy of the reaction by using the bond energies and heat of formation okay, so to calculate the enthalpy of reaction first you have to write the chemical reaction so we have to find out the heat of reaction from bond energies and the heat of formation so for this first you have to write the chemical reaction and the chemical reaction is ch2 double bond ch2 which is ethine so plus water gives rise to cs3 ch2 which is ethanol so this is the chemical reaction and if you'll draw the structure then it will be equals then it will be like so this is the ethine plus water and and it gives rise to ethanol.
01:23
So this is ethin and this is ethanol.
01:27
Ethin and this is ethanol.
01:33
So to calculate the heat of reaction from the bond energies, we have to calculate the heat of reaction.
01:42
We have to find out the heat of reaction.
01:47
The heat of reaction will be equals to energies of old bond breaking plus energies of new bond formation.
01:55
So heat of reaction will be equals to energies of old bond breaking plus energies of new bond formation.
02:22
Energy is of new bond formation.
02:35
So energies of old burn breaking will be equals to summation of 4 into bond energy of of ch because ch bond in the ethin side is c4 so bond energy of ph plus bond energy of cc that is c double point c plus bond energy 2 into bond energy of oh h so here oh bond is 2 so bond energy of o h into 2 minus minus, sorry, plus summation of.
03:29
So here the ch bond is 5.
03:32
So 5 multiplied by the bond energy of ch plus the bond energy of cc, the bond energy 1 into bond energy of cc plus 1 into the bond energy of cc plus 1 into the bond energy of o...