00006. Give the center of the circle and radius whose equation is \((x + 1)^2 + (y - 3)^2 = 16\). A. \((-1, 3)\), r = 4 B. \((3, -2)\), r = 4 C. \((3, 2)\), r = 1 D. \((6, -4)\), r = 4
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Given equation: (X T) + (y-3)" = 16 To rewrite it in standard form, we need to complete the square for both x and y terms. For the x term: (X T) = (x - 0)^2 Show more…
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