00:01
Hello students, in the first question we have provided with a graph which showing that the periodic wave traveling and we have the points a, b, c.
00:11
We have to look at the motion of them between a and b and b and c.
00:17
So, between a and b the particle is moving upward and in between b and c they are downward.
00:27
So, we can conclude from the fact that in the points which are moving in the x direction the positive slope moves downward and negative will be upward.
00:43
So, we can say that upward motion from a to b and downward from b to c.
00:58
Now, in the second question we have provided with the graph which shows that the speed of sound moving in a medium that is equal to 3 into 10 raise to 3 meter per second and time is given in milliseconds.
01:17
We have to calculate its lambda.
01:19
So, we have the equation lambda is equal to velocity into time.
01:26
So, for one period it is 2.
01:28
So, we have 3 into 10 raise to 3 into 2 into 10 raise to minus 3.
01:36
Thus we have the wavelength 6 meter.
01:39
So, the wavelength for the given figure we have lambda is equal to 6 meter.
01:46
Now, moving into the next question.
01:48
The question should explain about two canoes which are 10 meter apart.
01:55
So, the distance between the canoes is 10 meter and they are each of half way.
02:00
So, we have the wavelength will be equal to 2d that is 20 meter and they are having a speed of calculating the speed with time is 4 seconds.
02:18
So, we can write equation connecting velocity and lambda v is equal to lambda by t that is equal to 20 meter divided by 4 seconds that is 5 meter per second.
02:33
So, speed of the will be equal to 5 meter per second...