Estimate how long it will take to heat a cup of soup assume...

Estimate how long it will take to heat a cup of soup (assume this is 250 mLmL of water) from 20 ∘C∘C to 77 ∘C∘C. Ignore the heat loss to the surrounding environment. What will be the equilibrium temperature when a 275 gg block of copper at 245 ∘C∘C is placed in a 155 gg aluminum calorimeter cup containing 875 gg of water at 12.0 ∘C∘C

Transcript

00:01 So let's start the explanation of the question.

00:14 So in this question we have some values and we know that we wrote down the m h2o which is equal to 150 .0 gram and the mcu which is equal to 125 .0 gram and the mcu which is equal to 121 .0 gram and the value of t.

01:09 H2o which is equal to 25 .1 degree and on the other hand the c the t c u which is equal to 100 point 100 4 degree centigrade and the delta t h2o and the delta t h2 o which is equal to 5 degrees centigrade and the ccu which is equal to 0 .385 0 .385 the unit is jol divided by gram per kelvin gram per kelvin.

02:38 So on the other hand we can say that the c ch2o ch2o which is equal to 4 .18 4 .18 jol over g k gram kelvin and on the other hand the value of tf the value of tf which is equal to which is equal to 30 .1 degree centigrade and the value of delta tcu which is equal to minus 70 .m .3 degree centigrade.

03:46 So we know that the formula which is equal to the q which is equal to mc delta t and we know that the q which is equal to 1 to 1 to 1 .1 .1 .0 gram into 0 .385 into 0 .385 into 0 .385 into 0 .703.

04:36 So this is the complete equation and on the other hand the qh2o the qh2o which is equal to 1 .50 gram into 4 .18 4 .18 now so the q cu which is equal to minus 3275 minus 3275 joan this is the the first value we have required and now finding the value of qh2o so which is equal to which is equal to 31 35 30135 this is the value of qh2o this is the second value we have required so on the other hand now we discuss the point c in point c we know that the q h2o and the qc value we know this so we know that the delta t which is equal to five degrees centigrade and we know that the value we have further simplify this equation the formula which is q h2o minus q c divided by 5k so now we have putting the values 30 to 75 jule this is the value of qc minus the value of qh2o which is 3135 divided by the value of delta t which is 5 kelvin...

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