00:01
The function, h of x, is equal to 1 over x plus 2.
00:06
For all x, it is defined to 1 .6.
00:12
Number of the number of the length is equal.
00:15
So in first a part, you need to find the right hand point, that is the r4.
00:22
So first find the del x, that is a v negative a n, that is a 6 negative 1 of 4, which is equal to 5 over 4.
00:35
Therefore, area, therefore, sorry, we can find the sub interval that is the first will be 1.
00:49
0 .9 over 4.
00:52
Second will be 9 over 4 to 7 over 2.
00:56
3rd will be 7 over 2.
01:00
2 19 over 4 and last will be 19 over 4 to 6.
01:09
So from here we can find the point.
01:12
That is x0 is equal to 1 x1 is equal to 9 of 4 x2 is equal to 7 over 2 and x3 is equal to 19 over 4 and x4 is equal to 6 so the r4 can be calculated as l x bracket f of x1 plus aph of x2 plus a f of x3 plus a for x4 that is tell us that is a 5 over 4 a f of x1 that is f of 9 over 4 plus a f of 7 over 2 plus f of 19 over 4 plus f of 6 it can retain as 5 over 4 in bracket 1 over 2 plus 9 over 4 plus 1 over 2 plus 7 over 2 plus 7 over 2 plus 19 over 4 plus 1 over 2 plus 6...