00:01
Hello students in this question we have to estimate the monetary cost of delivering 100 ,000 millimeter irrigation water per year to irrigate a one hectare reduced field.
00:13
So to estimate the monetary cost of delivering 1000 millimeter of irrigation water per year to one hectare by pumping a depth pumping of water from a depth of 100 meter.
00:32
That is the first thing.
00:34
Ok, first thing is pumping.
00:36
Second thing is desalination.
00:38
So pumping groundwater first we need to calculate the energy required.
00:43
So 100 meter it will be equal to.
00:47
So let's first calculate the the the potential energy.
00:54
So potential energy will be equal to m times g times h right or you can write down it is the weight of the water times gravitational acceleration times head.
01:08
So weight is equal to 1000 kilogram per meter cube.
01:13
That is the weight density times 9 .8 meter per second times 1000 centimeter per 100 centimeter per meter.
01:27
That will give you a value of 9 .8 times 10 to the power 6.
01:35
This is a centimeter centimeter per meter joules per meter square.
01:42
So that is the the potential energy.
01:45
So energy required energy required required is equal to 9 .8 times 10 to the power 6 which is which is divided by the potential.
02:02
We can convert 1 kilowatt into potential energy.
02:05
So this is 1 kilowatt.
02:07
So 1 kilowatt will be equal to 3 .6 times 10 to the power 6.
02:11
That is equal to 3 .6 times 10 to the power 6.
02:14
So that will give you the energy value which will be equal to 2 .72 kilowatt hour per meter cube.
02:24
That will be the energy.
02:26
So the total energy requirement total energy is equal to is 2 .72 times 1000 meter cube.
02:42
So that will be equal to 2720 kilowatt.
02:48
So this is the total energy requirement for the pumping from 100 meter depth.
02:55
Okay, so that is the energy requirement.
02:58
This is actually 1000 meter right.
03:04
So this is supposed to be 10000.
03:08
Okay, so 100 meter 1 centimeter is equal to 100...