00:01
Hello students, in this question, the boiling point of the vaporization process is given which is equal to 35 degree celsius and the enthalpy change for the vaporization process is given which is equal to 27 .5 kilojoule per mole.
00:14
We have to find out the del s that is the entropy change for the vaporization process.
00:19
First of all, we want to know what is vaporization is.
00:25
The vaporization is the process in which the compound in the liquid state will be converted to the compound in the vapor state.
00:33
The temperature corresponding to this process is called as boiling point.
00:37
The boiling point is the temperature at which the component in the liquid state will be converted to the vapor state.
00:44
Here, the boiling point is equal to 35 degree celsius.
00:47
We have to convert this into kelvin by adding 273 to this.
00:52
On adding, we will get 308 kelvin...
