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Hello students, hope you all doing great.
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In this question we are asked to find out the enthalpy of this given reaction using the given three reactions.
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In the first step, we will reverse the reaction that reverse reaction number one.
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Reverse reaction one.
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Doing so, we have 2c plus 3co2 plus 3h2o gives 3o2 plus ch3ch2oh and hence its enthalpy will also change.
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So, we have enthalpy number one is equals to 1368 .2 kj.
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Next, we are given reaction number two.
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In reaction number two, we will multiply this reaction by two.
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Doing so, enthalpy also gets multiplied by two.
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We will multiply reaction number three by three and hence this also gets multiplied by three.
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After multiplying, we will add reaction one plus reaction two plus reaction three...