00:01
Hello everyone, let's start the question.
00:03
In the first part of this question, we are provided with a chemical reaction and we have to balance it out by using the half reaction method.
00:11
Now in this case, i have initially written the reaction, complete reaction, by mentioning the oxidation state of each of the elements which are involved in this case.
00:20
If we proceed by the second step, in the second step, we will be identifying and we'll write out all the redox couples in the reaction.
00:28
We will identify which reactants are being oxidized and which are being reduced.
00:33
For example, if we can see here in this case, this sodium oxalate, in this case on the reactant side, it is going from oxidation state plus 1 to plus 1 in case of sodium, but sulfur is in plus 6 here.
00:49
So we can say that na2, c2, o4, because here there is the oxidation going on.
01:00
It oxidizes to co2 then this will be considered to be as our oxidation half cell and if we talk of the species potassium permanganate which is kmno4 it is undergoing reduction from mn plus 7 to mn plus 2 that is mnso4 which is present on the react inside this will be our reduction half cell then if we combine these two redox couples into two reactions, one for the oxidation and one for the reduction, we can mention it here.
01:38
Moving on to the next step, now we will proceed by balancing the oxidation half cell and the reduction half cell.
01:47
If in case of oxidation, we check, we will balance the other atoms except hydrogen and oxygen, we can use any of the species that appear in the skeletal equation for this purpose.
01:58
Keeping in mind that reaction should be added only to the left side and product should be added to the right side.
02:05
So if we proceed with the oxidation half cell, the reaction will be written in this manner.
02:12
Na2c2o4, which is our sodium oxalate because the reaction is taking place in acidic medium.
02:17
H2so4 is being added.
02:19
Then on the product side, we will be writing 2 co2 along with the balancing plus na2 so4, that is sodium sulphate.
02:29
If we talk of the reduction of cells, the reaction will be written in this manner.
02:34
2 times of kmno4, that is potassium per manganate, is added to 3 times of h2so4, which is our fulphuric acid.
02:43
And on the product side, we will write 2mn so4 plus k2so4, k2so4, that is potassium sulfate with eight water molecules.
02:57
Then in the next step, we will be proceeding...