Question

Evaluate the following by integrating by parts \(\int (4x^3 - 9x^2 + 7x + 3)e^{-x} dx\)

          Evaluate the following by integrating by parts \(\int (4x^3 - 9x^2 + 7x + 3)e^{-x} dx\)
        
Evaluate the following by integrating by parts ∫ (4x^3 - 9x^2 + 7x + 3)e^-x dx

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Evaluate the following by integrating by parts J(4x3 - 9x2+7x+3)e-xdx
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Transcript

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00:01 Let's evaluate the given integral.
00:03 The first thing to observe here is that the numerator has larger degree than the denominator.
00:09 So we should do polynomial division to simplify before we even consider partial fractions.
00:16 So let's do the division here.
00:18 X to the 4 divided by x squared.
00:21 That's just x squared.
00:24 Let's go ahead and multiply that out.
00:29 Then we subtract.
00:32 And we're left over with x plus 2 because we have cancellation here.
00:37 So this tells us that we can rewrite the integral as x plus 2, oops, excuse me, x squared, this is the quotient, and then we have our remainder x plus 2 over the original denominator, x squared plus 9.
01:01 So this is a simpler looking integral than the original.
01:05 There's really no need for partial fractions here because this term over here already is a partial fraction.
01:13 We have a quadratic in the denominator that does not factor, and then you have your ax plus b in the numerator.
01:20 So really, we're ready to integrate.
01:24 Let's break this into three integrals.
01:27 And then we could split up this fraction.
01:30 This is just x over x squared plus 9 plus 2 over x squared plus 9.
01:38 So let's go ahead and integrate each of those.
01:47 And then for the last one, let's go ahead and pull out that 2.
01:55 And now we have three integrals.
02:01 So the first one, just use the power rule...
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