Evaluate the function at the given values of x. Round to 4 decimal places, if necessary. $f(x) = \left(\frac{1}{3}\right)^x$ Part 1 of 4 $f(-2) = 9$ Part: 1 / 4 Part 2 of 4 $f(2.2) = \Box$
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Part 1 of 4 has already been completed and shows $f(-2) = 9$. Let's verify this. For $x = -2$: $f(-2) = \left(\frac{1}{3}\right)^{-2}$ Using the property $a^{-n} = \frac{1}{a^n}$, we have: $f(-2) = \frac{1}{\left(\frac{1}{3}\right)^2}$ $f(-2) = Show more…
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