00:01
So for this problem, we're given two points.
00:03
We have negative 3, comma, 2, and then 0, 11.
00:16
And we have to determine what the a and k value are in the equation y is equal to a times x plus 2 squared plus k, so that both points are on.
00:49
The graph of the function.
00:52
So to start off, i'm going to label each of the point.
00:57
So we have x, y, x, y, x, y, and i'm going to substitute or plug in each point into the equation.
01:09
So starting with negative three comma two, we have two is equal to.
01:15
We don't know what a is, so a times negative 3 plus 2 squared plus k so then according to order of operations we have to do whatever is in the parentheses first so we have a times negative 3 plus 2 is negative 1 squared plus k then negative 1 square which is the same thing as 2 2 2 times negative 1 is just 1 so we have 1 a plus k so that's all we can simplify for now.
01:56
Then for the point zero come 11 we're going to plug that into the equation.
02:00
We have 11 is equal to a times zero plus two squared plus k.
02:19
We have 11 is equal to a times zero plus 2.
02:27
So we have 2 squared plus k.
02:34
2 square is the same thing as 2 times 2, which is 4.
02:38
So we have 4 times a plus k.
02:45
So now that we have these two equations, we are going to solve for a by subtracting the two equations.
03:00
So this is one way to solve a system of equations by elimination.
03:06
So we we're eliminating the k to solve for a and then we'll go back to trying to find the k value so i wrote the two equations one on top of the other and so if we subtract the equations from each other k minus k number minus itself will always be zero so that crosses out then we have 11 minus two which is nine and then for a minus three one a is three a and then to solve for what a is a is and then to solve for what a is we have to get the three to the other side, so we have to do the opposite or the inverse operation.
03:44
So the opposite of multiplying by three is dividing by three.
03:47
So we have three divided by three, which is just one, so we're left with a is equal to, and then nine divided by three is three.
03:55
So we found our a value, and to find our k value, we're going to substitute a into the equation, and i'm going to choose the point zero comma 11 to substitute as well.
04:08
So we have y is equal to a is three.
04:16
Then i'm going to just rewrite the equation with our a value...