00:01
Okay, let's start answering first question a.
00:05
Question a, as for the mass of the water needed to be evaporated to cool the body of the man by 1 degree structures.
00:16
Given that, the mass of the man is 70 kilogram and specific heat of his body is 3 ,480 joules per kilogram.
00:34
And the heat of vaporization of water is 2 .42 times 10 raised to 6 jous per kilogram.
00:47
And the temperature change since we are cooling the body, this is negative 1 degrees, since there is a decrease in temperature from initial to final.
01:02
Now, in this situation, we have two kinds of heat.
01:06
First, we have the heat.
01:09
Heat that is associated with the change in phase of the water since we are changing the water from liquid to vapor.
01:22
The formula of heat transfer in this case is mass of the water multiplied by the heat of vaporization.
01:34
In this case this heat is positive since we are having heat to the body.
01:40
Now the other heat, this is a positive.
01:42
Situation is the heat associated with the temperature change of the man...