Question

Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150 MW by the radioactive decay of fission products. This heat transfer causes a rapid increase in temperature if the cooling system fails. [Properties of steel vessel: cp=470 J/kg.oC, melting point=1430 oC and Lf=270 kJ/kg] a) Calculate the rate of temperature increase in degrees Celsius per second (ºC/s) if the mass of the reactor core is 1.60×105 kg and it has an average specific heat of 0.3349 kJ/kgº C. [2 marks] b) How long would it take to obtain a temperature increase of 200ºC? [2 marks] c) Considering the same rate of thermal energy transfer (150 MW) to the steel containment vessel, how long it will take to melt 1.00% of the steel vessel? (Assume, the initial temperature and mass of steel containment vessel are 300oC and 5×105 kg respectively.) [4 marks] d) Make a graph of temperature versus time for the process in question (c). [2 marks]

          Even when shut down after a period of normal use, a large commercial nuclear reactor transfers
thermal energy at the rate of 150 MW by the radioactive decay of fission products. This heat
transfer causes a rapid increase in temperature if the cooling system fails. [Properties of steel
vessel: cp=470 J/kg.oC, melting point=1430 oC and Lf=270 kJ/kg]
a) Calculate the rate of temperature increase in degrees Celsius per
second (ºC/s) if the mass of the reactor core is 1.60×105 kg and it has
an average specific heat of 0.3349 kJ/kgº C. [2 marks]
b) How long would it take to obtain a temperature increase of 200ºC? [2
marks]
c) Considering the same rate of thermal energy transfer (150 MW) to the
steel containment vessel, how long it will take to melt 1.00% of the
steel vessel? (Assume, the initial temperature and mass of steel
containment vessel are 300oC and 5×105 kg respectively.) [4 marks]
d) Make a graph of temperature versus time for the process in question
(c). [2 marks]
        
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Added by Rishva S.

College Physics for AP® Courses
College Physics for AP® Courses
Irina Lyublinskaya, Gregg Wolfe, Douglas…
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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150 MW by the radioactive decay of fission products. This heat transfer causes a rapid increase in temperature if the cooling system fails. [Properties of steel vessel: cp=470 J/kg.oC, melting point=1430 oC and Lf=270 kJ/kg] a) Calculate the rate of temperature increase in degrees Celsius per second (ºC/s) if the mass of the reactor core is 1.60×105 kg and it has an average specific heat of 0.3349 kJ/kgº C. [2 marks] b) How long would it take to obtain a temperature increase of 200ºC? [2 marks] c) Considering the same rate of thermal energy transfer (150 MW) to the steel containment vessel, how long it will take to melt 1.00% of the steel vessel? (Assume, the initial temperature and mass of steel containment vessel are 300oC and 5×105 kg respectively.) [4 marks] d) Make a graph of temperature versus time for the process in question (c). [2 marks]
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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150 MW by the radioactive decay of fission products. This heat transfer causes a rapid increase in temperature if the cooling system fails (1 watt = 1 joule/second or 1 W = 1 J/s and 1 MW = 1 megawatt) . (a) Calculate the rate of temperature increase in degrees Celsius per second $\left(^{\circ} \mathrm{C} / \mathrm{s}\right)$ if the mass of the reactor core is $1.60 \times 10^{5} \mathrm{kg}$ and it has an average specific heat of 0.3349 $\mathrm{kJ} / \mathrm{kg}^{\circ} \cdot \mathrm{C}$. (b) How long would it take to obtain a temperature increase of $2000^{\circ} \mathrm{C}$ metals holding the radioactive materials to melt? (The initial rate of temperature increase would be greater than that calculated here because the heat transfer is concentrated in a smaller mass. Later, however, the temperature increase would slow down because the $5 \times 10^{5}$ -kg steel containment vessel would also begin to heat up.)

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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of $150 \mathrm{MW}$ by the radioactive decay of fission products. This heat transfer causes a rapid increase in temperature if the cooling system fails (1 watt $=1$ joule/second or $1 \mathrm{W}=1 \mathrm{J} / \mathrm{s}$ and $1 \mathrm{MW}=1 \text { megawatt }) . \quad$ (a) Calculate the rate of temperature increase in degrees Celsius per second ( $^{\circ} \mathrm{C} / \mathrm{s}$ ) if the mass of the reactor core is $1.60 \times 10^{5} \mathrm{kg}$ and it has an average specific heat of $0.3349 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}$. (b) How long would it take to obtain a temperature increase of $2000^{\circ} \mathrm{C},$ which could cause some metals holding the radioactive materials to melt? (The initial rate of temperature increase would be greater than that calculated here because the heat transfer is concentrated in a smaller mass. Later, however, the temperature increase would slow down because the $500,000-\mathrm{kg}$ steel containment vessel would also begin to heat up.)

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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150 MW by the radioactive decay of fission products. This heat transfer causes a rapid increase in temperature if the cooling system fails (1 watt $=1$ joule/second or $1 \mathrm{W}=1 \mathrm{J} / \mathrm{s}$ and $1 \mathrm{MW}=1$ megawatt) . (a) Calculate the rate of temperature increase in degrees Celsius per second ( $^{\circ} \mathrm{C} / \mathrm{s}$ ) if the mass of the reactor core is $1.60 \times 10^{5} \mathrm{kg}$ and it has an average specific heat of $0.3349 \mathrm{kJ} / \mathrm{kg}^{\circ} \cdot \mathrm{C} .$ (b) How long would it take to obtain a temperature increase of $2000^{\circ} \mathrm{C},$ which could cause some metals holding the radioactive materials to melt? (The initial rate of temperature increase would be greater than that calculated here because the heat transfer is concentrated in a smaller mass. Later, however, the temperature increase would slow down because the $5 \times 10^{5}$ -kg steel containment vessel would also begin to heat up.)

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